fix: get all users on the same GPU

Problem:
    Sometimes, multiple users may run the different program on the same
    GPU if the VRAM is enough.
    But the original program only get the first username on the webpage
    so that we may lose some users.

Solution:
    For one servers, I get all GPU's name and all usernames on this line
    on the webpage.

    So I will return a dict contains all GPU names and username on every
    GPU.

main.py

@@ -77,30 +77,40 @@ def get_server_gpu_status() -> list:
         soup = BeautifulSoup(box, 'html.parser')
         # get server name
         server_name = soup.find('span', class_='f7').text.replace(' ', '')
-
+        gpu_names = []
-        # get GPU name
-        gpu_name = soup.find('span', class_='f4').text.replace(' ', '')
 
         users = []
         gpus = box.split('\n')
-        for i in gpus[1:]:
+        for i in gpus[:]:
+            if 'f6' in i:           # if this line is for a single GPU informations
                 soup = BeautifulSoup(i, 'html.parser')
 
                 # get all users who is using this server's GPU resources.
-            user_obj = soup.find('span', class_='f0')
+                user_objs = soup.findAll('span', class_='f0')
+                user_in_this_gpu = set()
+                
+                # get users on this GPU
+                for user_obj in user_objs:
                     if user_obj != None:
                         username = user_obj.text
                         if username != 'gdm':
-                    users.append(username)
+                            user_in_this_gpu.add(username)
+
+                # get gpu names
+                gpu_name = soup.find('span', class_='f4').text.replace(' ', '')
+
+                # log gpu name & users on this GPU
+                gpu_names.append(gpu_name)
+                users.append(list(user_in_this_gpu))
 
         servers.append({
             'name': server_name,
             'users': users,
-            'gpu': gpu_name
+            'gpu': gpu_names
         })
     return servers
 
-def filter(server_status: dict, limit: int = 2) -> list:
+def filter(server_status: list, limit: int = 2) -> list:
     '''
         You can set some rule here.
         it will return the a list which contains the username that exceed the limit.
@@ -110,14 +120,18 @@ def filter(server_status: dict, limit: int = 2) -> list:
         I add this function beacause that we may need more filter rules. we can add some rules in this function easily
 
         Input:
-            server_status (dict): e.g. {'name': 'cml5', ...}
+            server_status (list): from get_server_gpu_status()
             limit (int): GPU limit (default: 2)
         Output:
-            violators (list): a violator list(set) e.g. [ {'user': 'snsd0805', 'gpu': 3}] means that the violator 'snsd0805' is using 3 GPU.
+            violators (list): a violator list(set) e.g. [ {'user': 'snsd0805', 'usage': [{'server': 'cml5', 'gpu': 'NVDIA3090', 'number': 3}...] }] means that the violator 'snsd0805' is using 3 GPU.
     '''
     violators = []
 
     counter = {}
+
+    for server in server_status:
+        print(server)
+    '''
     for user in server_status['users']:
         if user not in counter:
             counter[user] = 1
@@ -130,6 +144,7 @@ def filter(server_status: dict, limit: int = 2) -> list:
                 'user': k,
                 'gpu': v,
             })
+    '''
     return violators
 
 def mail_notify(server_name: str, gpu_name: str, violators: list) -> None:
@@ -181,9 +196,15 @@ def mail_notify(server_name: str, gpu_name: str, violators: list) -> None:
 
 if __name__ == '__main__':
     server_status = get_server_gpu_status()
+    for i in server_status:
+        print(i)
+
+    violators = filter(server_status, 2)
+    '''
     for server in server_status:
         print(server['name'], server['gpu'])
         violators = filter(server, 2)
         print(violators)
         mail_notify(server['name'], server['gpu'], violators)
         print("=" * 20)
+    '''